Mentat

1 program Added 2026-03-11T10:00:00Z Agent: claude-codeModel: claude-sonnet-4-6WebSearch: disabled Evidence Report issue View issues
Aliases: The Mentat Programming Language
Provenance: commit 5652968a77 · authored 2026-03-11T18:54:11+01:00 · agent claude-code · model claude-sonnet-4-6

Sources mentioning this language

2 sources · pl_id: pl/mentat
LLM (this repo) · 1Pldb

Related languages

Jai (0.59)Piet (0.56)J (0.55)S (0.55)Vlang (0.55)

Real programs from Software Heritage

No SWH evidence indexed yet for this language. (Either the SWH mining hasn't reached this language's extensions, or no matching files exist in the archive.)

Programs collected by LLM agents experimental · unverified

Gathered by LLM agents during the experiment that started this catalogue. They are not verified: the agent names an origin, but a program can be altered or invented — an audit found one attributed to a file that does not exist, in a syntax the language does not have. Prefer the programs archived by Software Heritage above. The catalogue's goal is the languages themselves, grounded in sources (PLDB, Wikipedia, Rosetta Code, …), with real archived programs; these examples may be dropped.

Parallel Sum

Provenance: commit 5652968a77 · authored 2026-03-11T18:54:11+01:00 · agent claude-code · model claude-sonnet-4-6 · WebSearch disabled
code.cc · license: CC BY-SA 4.0 · added: 2026-03-11T10:00:00Z
/* Mentat example: Parallel sum computation
   The Mentat Programming Language by Andrew Grimshaw, UVA */

#include <mentat/mentat.h>
#include <stdio.h>

mentat class Summer : public MObject {
public:
    int sum(int start, int end);
};

int Summer::sum(int start, int end) {
    int total = 0;
    for (int i = start; i <= end; i++) {
        total += i;
    }
    return total;
}

int main(int argc, char *argv[]) {
    Summer s1, s2;

    /* Parallel method invocations - return immediately */
    int* h1 = s1.sum(1, 50);
    int* h2 = s2.sum(51, 100);

    /* Dereference blocks until results are available */
    printf("Sum of 1..100 = %d\n", *h1 + *h2);

    return 0;
}

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